Let the 100 wrestlers be $p_1, p_2, ... , p_{100}$. Assume WLOG that the strength of $p_1<p_2<...<p_{100}$. Then $p_{100}$ will win both fights. Let $p_{100}$'s fights be with $p_{99}$ and $p_1$ and those of $p_1$ with $p_{100}$ and $p_2$. For all other $p_n$, let their fights be with $p_{n+1}$ and $p_{n-1}$. Then all of $p_2 ... p_{99}$ win one fight and lose the other, while $p_1$ loses both and $p_{100}$ wins both, therefore being the only awardee. Hence the answer is $\fbox{1}$.