Let $O$ be the circumcenter of an acute-angled triangle $ABC$. A line passing through $O$ and parallel to $BC$ meets $AB$ and $AC$ in points $P$ and $Q$ respectively. The sum of distances from $O$ to $AB$ and $AC$ is equal to $OA$. Prove that $PB + QC = PQ$.
Problem
Source: Sharygin Geometry Olympiad 2012 - Problem 12
Tags: geometry, circumcircle, incenter, geometry unsolved