Syler 29.04.2010 12:12 Sum of $ 100 $ natural distinct numbers is $ 9999 $. Prove that $ 2006 $ divide their product.
JBL 29.04.2010 15:47 This is just ridiculously false: $1 + 2 + \ldots + 58 + 60 + 61 + \ldots + 100 + 5008 = 9999$.