In a triangle, each median forms an angle with the side it is drawn to, which is less than $\alpha$. Prove that one of the angles of the triangle is greater than $180^\circ - \frac{4}{3}\alpha$. Proposed by S. Berlov
Source: 239 Open MO, 2018, Senior League, Problem 7
Tags: geometry, Geometry inequality
In a triangle, each median forms an angle with the side it is drawn to, which is less than $\alpha$. Prove that one of the angles of the triangle is greater than $180^\circ - \frac{4}{3}\alpha$. Proposed by S. Berlov