In triangle $ABC$ the median $BM$ is equal to half of the side $BC$. Show that $\angle ABM = \angle BCA + \angle BAC$. (Proposed by Anton Trygub)
Source: Kyiv City MO 2022 Round 2, Problem 7.3
Tags: geometry
In triangle $ABC$ the median $BM$ is equal to half of the side $BC$. Show that $\angle ABM = \angle BCA + \angle BAC$. (Proposed by Anton Trygub)
