Inside a rhombus $ABCD$ with $\angle BAD=60$, points $F,H,G$ are choosen on lines $AD,DC,AC$ respectivily such that $DFGH$ is a paralelogram. Show that $BFH$ is a equilateral triangle.
Problem
Source: Bolivian Cono Sur TST 2021 Day 2 P1
Tags: geometry, rhombus, parallelogram, Equilateral Triangle, Bolivia, Cono Sur TST, TST
