Let $ABCD$ and $A_1B_1C_1D_1$ be convex quadrangles in a plane, such that $AB=A_1B_1$, $BC=B_1C_1$, $CD=C_1D_1$ and $DA=D_1A_1$. Given that diagonals $AC$ and $BD$ are perpendicular to each other, prove that the same holds for diagonals $A_1C_1$ and $B_1D_1$.