Problem

Source: XII All-Ukrainian Tournament of Young Mathematicians, Qualifying p15

Tags: geometry, trigonometry, 3D geometry, geometric inequality, Ukrainian TYM



Given a triangular pyramid $SABC$, in which $\angle BSC = \alpha$, $\angle CSA =\beta$, $\angle ASB = \gamma$, and the dihedral angles at the edges $SA$ and $SB$ have the value of $\phi$ and $\delta$, respectively. Prove that $\gamma > \alpha \cdot \cos \delta +\beta \cdot \cos \phi.$$