Let $CH$ be the altitude of the triangle $ABC$ drawn on the board, in which $\angle C = 90^o$, $CA \ne CB$. The mathematics teacher drew the perpendicular bisectors of segments$ CA$ and $CB$, which cut the line CH at points $K$ and $M$, respectively, and then erased the drawing, leaving only the points $C, K$ and $M$ on the board. Restore triangle $ABC$, using only a compass and a ruler.
Problem
Source: 2015 XVIII All-Ukrainian Tournament of Young Mathematicians named after M. Y. Yadrenko, Qualifying p21
Tags: geometry, construction, right triangle, Ukrainian TYM