The circumradius of a tetrahedron $ ABCD$ is $ R$, and the lenghts of the segments connecting the vertices $ A,B,C,D$ with the centroids of the opposite faces are equal to $ m_a,m_b,m_c$ and $ m_d$, respectively. Prove that: $ m_a+m_b+m_c+m_d\leq \dfrac{16}{3}R$
Problem
Source: Moldova NMO 2002 grade 11 problem nr.8
Tags: inequalities, geometry, 3D geometry, tetrahedron, circumcircle