It is possible to place the $2014$ points in the plane so that we can construct $1006^2$ parralelograms with vertices among these points, so that the parralelograms have area 1?
Source: Archimedes Junior 2015
Tags: combinatorics
It is possible to place the $2014$ points in the plane so that we can construct $1006^2$ parralelograms with vertices among these points, so that the parralelograms have area 1?