Let $O$ be the center of a regular triangle $ABC$. From an arbitrary point $P$ of the plane, the perpendiculars were drawn on the sides of the triangle. Let $M$ denote the intersection point of the medians of the triangle , having vertices the feet of the perpendiculars. Prove that $M$ is the midpoint of the segment $PO$.
Problem
Source: Sharygin 2005 IX CR 9
Tags: Equilateral, Equilateral Triangle, perpendicular, midpoint, Centroid, geometry