Problem

Source: Oral Moscow Geometry Olympiad 2015 grades 10-11 p4

Tags: geometry, circumcircle, equal angles, Tangents, midpoints



In triangle $ABC$, point $M$ is the midpoint of $BC, P$ is the intersection point of the tangents at points $B$ and $C$ of the circumscribed circle, $N$ is the midpoint of the segment $MP$. The segment $AN$ intersects the circumscribed circle at point $Q$. Prove that $\angle PMQ = \angle MAQ$.