Let $M$ be the intersection point of the medians $AD$ and $BE$ of a right triangle $ABC$ ($\angle C=90^\circ$). It is known that the circumcircles of triangles $AEM$ and $CDM$ are tangent. Find the angle $\angle BMC.$
Problem
Source: Kyiv mathematical festival 2018
Tags: Kyiv mathematical festival, geometry, tangent circles
