parmenides51 14.11.2021 03:51 Find a multiple of $2018$ whose decimal expansion's first four digits are $2017$.
BackToSchool 14.11.2021 17:04 The smallest four are here. \begin{align*} 20177982 &= 20180000-2018 \times 1\\ 20175964 &= 20180000-2018 \times 2 \\ 20173946 &= 20180000-2018 \times 3 \\ 20171928 &= 20180000-2018 \times 4 \end{align*}You can find as many as you want. Just do like this: \begin{align*} 201800000 &- 2018\times 1\\ 2018000000 &- 2018\times 1 \\ 20180000000 &- 2018\times 1 \\ ......&...... \end{align*}